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6c^2=9c
We move all terms to the left:
6c^2-(9c)=0
a = 6; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·6·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*6}=\frac{0}{12} =0 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*6}=\frac{18}{12} =1+1/2 $
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